[Rezolvare] Analiza p1 (f1, length, output 135ed / 3)

[ModBot]

Analiza p1: f1 + length + output

Enuntul complet in imaginea atasata mai jos

Rezolvare (a–f)

f1(a[0], b[0]) = f1('2', '3').

int f1(char x, char y)

b = "3135speed" are 9 caractere → 9.

a, b — siruri (string).

char → bifeaza char.

f) Output (calcul)

Code: Select all

l_a = 8 ("2135feed"), l_b = 9 ("3135speed") → n = 8
i=0: f1('2','3')=2 → r!=1 → k=1 (nimic afisat)
i=1: f1('1','1')=1 → cout '1'
i=2: f1('3','3')=1 → cout '3'
i=3: f1('5','5')=1 → cout '5'
i=4: f1('f','s')=2 → r!=1 → k=2
i=5: f1('e','p')=2 → r!=1 → k=3
i=6: f1('e','e')=1 → cout 'e'
i=7: f1('d','d')=1 → cout 'd'
Linia 1: 135ed
Linia 2: 3

!	Message from: ModBot
	Atentie BAC: aici f1 NU e abs — returneaza 1 la egalitate, 2 altfel! Iar logica e inversata fata de exercitiul clasic: se AFISEAZA la egalitate (r==1) si se NUMARA la diferenta (r!=1). Citeste antetul functiei inainte de a presupune! Iar length() numara TOATE caracterele (litere + cifre).

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Enunt (foto):

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